Assignment #13

In order to find the volume of the solid when revolving f(x)=1/x around the x-axis you must do V=integral of (1/x)dx*π  [0,∞) V=(ln∞-ln(1))*π V=π

In order to find the surface area you do
Surface Area=((1-(x^-4)^1/2))dx from [1,∞)*π*ʃ1/(x^2)dx = ∞

This isn't a paradox because the volume of the solid approaches π as the functions continues unto ∞ and while the surface area does not approach a definite integer while the function continues to approach ∞.