Assignment #8

1)

A)     ʃsin u du = -cos u + C
B)     ʃcos u du = sin u +C
C)     ʃtan u du = -ln |cos u| + C
D)     ʃcot u du = ln |sin u| + C
E)     ʃsec u du = ln |sec u + tan u| +C
F)     ʃcsc u du = -ln |csc u + cot u| + C

2)
You have to set u equal to 2x. This is because it is within the function of U^1/2. du then equals 2dx, but it cant because of (4x+1)dx